1. Tammy MacIntosh is known for her roles on television series The Flying Doctors, Police Rescue, Sea Patrol, the television film McLeod's Daughters which led to the acclaimed drama series of the same title, and played the role of Kaz Proctor in the prison drama series Wentworth, until her departure in June 2019.
Tammy MacIntosh graduated from the Western Australian Academy of Performing Arts, a division of Edith Cowan University.
Tammy MacIntosh is married to Mark Yeats and they have a son.
Tammy MacIntosh started out as a reporter for a children's show C'mon Kids in South Australia in the late eighties.
Tammy MacIntosh was a well-known face in her regular role of Kathy in Police Rescue.
Tammy MacIntosh played a main character in the first season of the BAFTA Award-winning BBC show, Jeopardy.
In 1998, Tammy MacIntosh appeared in the detective series Good Guys, Bad Guys.
Tammy MacIntosh joined the science fiction television series Farscape in late 2000.
Tammy MacIntosh was cast as Jool, a young Interion woman.
Tammy MacIntosh made her first appearance in the third-season episode "Self-Inflicted Wounds Part I: Could'a, Would'a, Should'a".
In 2002, Tammy MacIntosh was cast as Dr Charlotte Beaumont in the medical drama All Saints.
Tammy MacIntosh took the role of Charlotte as she saw the character as a new challenge.
Tammy MacIntosh had a recurring role on Sea Patrol portraying Commander Maxine "Knocker" White.
Tammy MacIntosh played Doctor Elizabeth "Mac" Macmillan in ABC's crime drama Miss Fisher's Murder Mysteries, and Doctor Amelia Ward in "Episode 9" of Crownies.
Tammy MacIntosh was considered for the role of Bea Smith in prison drama Wentworth.
Tammy MacIntosh later joined the cast in the third season as vigilante Kaz Proctor, alongside actresses Pia Miranda and Libby Tanner.
Tammy MacIntosh spoke with the production team at the end of series six to inform them that the upcoming seventh season would be her last as Kaz.
Tammy MacIntosh made a cameo appearance in The Drover's Wife and appeared in The Longest Weekend.